∑ DANEMATHICS
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Grade 8–9 · Constructions
Construction of Geometric Figures
MARKING GUIDELINE
Marks
29
Duration
45 minutes
Questions
3
Name:
Class:
Date:
Mark
/ 29
Instructions and Information
- Answer ALL the questions in this question paper.
- Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
- Show ALL calculations clearly.
- Show all units where applicable.
- Number the answers correctly according to the numbering system used in this question paper.
- A non-programmable calculator may be used, unless stated otherwise.
- Write neatly and legibly.
Question 1
[10 MARKS]Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.
- 1.1Which instrument is used to draw a circle of a given radius?(1)A)protractorB)pair of compasses✓C)rulerD)set squareAnswer: B — The compasses hold a fixed radius.
- A — a protractor measures angles
- C — a ruler measures straight lengths
- D — a set square gives right angles
- 1.2Which instrument measures the SIZE of an angle?(1)A)compassesB)protractor✓C)rulerD)pencilAnswer: B — A protractor is marked in degrees.
- A — compasses draw arcs
- C — a ruler measures length
- D — a pencil marks the paper but measures nothing
- 1.3To BISECT a line segment means to …(1)A)measure itB)cut it into two equal parts✓C)draw it longerD)draw it at 90°Answer: B — Bi- means two.
- A — measuring alone does not divide it
- C — that is producing it
- D — that is a perpendicular
- 1.4The perpendicular bisector of AB …(1)A)passes through A onlyB)cuts AB in half at 90°✓C)is parallel to ABD)is longer than ABAnswer: B — It does both jobs: bisects AND is perpendicular.
- A — it crosses the middle, not an endpoint
- C — a parallel line would never cross it
- D — its length is not fixed
- 1.5Before a triangle can be constructed from three given sides, the sides must satisfy …(1)A)all being equalB)the sum of any two being GREATER than the third✓C)all being differentD)one being a right angleAnswer: B — Otherwise the two shorter sides cannot meet.
- A — equal sides make one particular triangle, not a rule
- C — scalene is not required
- D — a right angle is not required
- 1.6Which set of lengths CANNOT form a triangle?(1)A)3 cm, 4 cm, 5 cmB)2 cm, 3 cm, 6 cm✓C)5 cm, 5 cm, 5 cmD)6 cm, 8 cm, 10 cmAnswer: B — 2 + 3 = 5, which is less than 6, so the sides cannot close.
- A — 3 + 4 > 5, so it works
- C — an equilateral triangle
- D — 6 + 8 > 10, so it works
- 1.7A 60° angle can be constructed with compasses alone because it is the angle of …(1)A)a squareB)an equilateral triangle✓C)a straight lineD)a hexagon's interiorAnswer: B — Every angle of an equilateral triangle is 60°.
- A — a square gives 90°
- C — a straight line gives 180°
- D — a regular hexagon's interior angle is 120°
- 1.8The angles of ANY triangle add up to …(1)A)90°B)180°✓C)360°D)270°Answer: B — This is true for every triangle.
- A — that is one right angle
- C — that is a quadrilateral
- D — that is three right angles
- 1.9To construct a line parallel to a given line, you copy …(1)A)the lengthB)the corresponding angle✓C)the midpointD)the perpendicularAnswer: B — Equal corresponding angles guarantee parallel lines.
- A — length does not fix direction
- C — a midpoint does not fix direction
- D — that constructs a perpendicular instead
- 1.10Arcs drawn during a construction should be …(1)A)rubbed out afterwardsB)left showing✓C)drawn in penD)drawn freehandAnswer: B — They are the evidence that the construction was done properly, and marks are awarded for them.
- A — erasing them removes the evidence
- C — constructions are drawn in pencil
- D — compasses must be used, not freehand
Answer grid — marking guideline
| 1.1 | A | B | C | D |
| 1.2 | A | B | C | D |
| 1.3 | A | B | C | D |
| 1.4 | A | B | C | D |
| 1.5 | A | B | C | D |
| 1.6 | A | B | C | D |
| 1.7 | A | B | C | D |
| 1.8 | A | B | C | D |
| 1.9 | A | B | C | D |
| 1.10 | A | B | C | D |
Question 2
[11 MARKS]Answer the following about constructions. You may use only a ruler and a pair of compasses, and you must leave all your construction arcs showing.
- 2.1Describe, step by step, how you would construct the perpendicular bisector of a line segment AB.(4)Open the compasses to more than half of AB (1)
With the point on A, draw arcs above and below AB (1)
Keeping the SAME radius, repeat with the point on B (1)
Join the two points where the arcs cross (1) - 2.2Explain why the compass radius must be MORE than half of AB.(3)If the radius is less than half of AB (1)
the two sets of arcs never meet (1)
so there are no crossing points to join (1) - 2.3Describe how you would construct an angle of 60° without using a protractor, and explain why the method works.(4)Draw a line and mark a point A on it (1)
With centre A draw an arc cutting the line at B (1)
With the SAME radius and centre B, draw an arc cutting the first at C; join AC (1)
AB = BC = AC, so △ABC is equilateral and every angle is 60° (1)
Question 3
[8 MARKS]A learner is asked to construct a triangle with sides of 7 cm, 9 cm and 13 cm, as sketched below.
- 3.1Show by calculation that this triangle CAN be constructed.(3)7 + 9 = 16 (1)
16 > 13 (1)
The two shorter sides are longer than the third, so the arcs will meet (1) - 3.2A second learner is asked to construct a triangle with sides 5 cm, 6 cm and 12 cm. Explain why this is impossible.(3)5 + 6 = 11 (1)
11 < 12 (1)
The two shorter sides cannot reach each other, so the arcs never cross (1) - 3.3Write down the general rule you used in the two questions above.(2)The sum of any two sides of a triangle (1)
must be greater than the third side (the triangle inequality) (1)
TOTAL: 29 marks
This question paper consists of 3 questions.