DANEMATHICS
FREE CAPS MATHS RESOURCES
Grade 10 · Equations & Inequalities
Literal Equations: Changing the Subject of a Formula
MARKING GUIDELINE
Marks
33
Duration
50 minutes
Questions
3
Name: 
Class: 
Date: 
Mark
  / 33
Instructions and Information
  1. Answer ALL the questions in this question paper.
  2. Answer QUESTION 1 by circling the letter (AD) in the answer grid at the end of that section.
  3. Show ALL calculations clearly.
  4. Show all units where applicable.
  5. Number the answers correctly according to the numbering system used in this question paper.
  6. A non-programmable calculator may be used, unless stated otherwise.
  7. Write neatly and legibly.

Question 1

[10 MARKS]

Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.

  1. 1.1
    Make x the subject of y = mx + c.
    (1)
    A)y − cm
    B)ym − c
    C)y + cm
    D)y − c − m
    Answer: A — Subtract c from both sides first, then divide the WHOLE side by m.
    • B — divided only the y by m — the c must be moved across first
    • C — added c instead of subtracting it
    • D — subtracted m instead of dividing by it
  2. 1.2
    Make r the subject of A = πr².
    (1)
    A)√(A ÷ π)
    B)A ÷ π
    C)√(Aπ)
    D)A² ÷ π
    Answer: A — Divide both sides by π to get r² = A/π, then take the square root.
    • B — stopped at r² and never took the square root
    • C — multiplied by π instead of dividing by it
    • D — squared A instead of square-rooting after dividing
  3. 1.3
    Make h the subject of V = 13πr²h.
    (1)
    A)3Vπr²
    B)V3πr²
    C)3Vπr
    D)Vπr²
    Answer: A — Multiply both sides by 3 to clear the third, then divide by πr².
    • B — divided by 3 instead of multiplying — the 1/3 is on the other side
    • C — dropped the square on the r
    • D — never cleared the 1/3 at all
  4. 1.4
    Make b the subject of P = 2(l + b).
    (1)
    A)P − 2l2
    B)P2 − 2l
    C)P − 2l
    D)P2l
    Answer: A — Divide both sides by 2 to get l + b = P/2, then subtract l — which is (P − 2l)/2.
    • B — divided the P by 2 but not the 2l
    • C — never divided by the 2 at all
    • D — divided by 2l instead of subtracting l
  5. 1.5
    Make x the subject of ax + b = cx + d.
    (1)
    A)d − ba − c
    B)d + ba + c
    C)b − da − c
    D)d − bc − a
    Answer: A — Collect the x terms: ax − cx = d − b, so x(a − c) = d − b.
    • B — added the terms instead of moving them across, which changes their signs
    • C — moved b across without changing its sign
    • D — swapped a and c when factorising
  6. 1.6
    Make a the subject of v² = u² + 2as.
    (1)
    A)v² − u²2s
    B)v² + u²2s
    C)v − u2s
    D)v² − u²s
    Answer: A — Subtract u² from both sides, then divide by 2s.
    • B — added u² instead of subtracting it
    • C — square-rooted v² and u² separately, which cannot be done across a subtraction
    • D — forgot to divide by the 2 as well as the s
  7. 1.7
    Make C the subject of F = 95C + 32.
    (1)
    A)59(F − 32)
    B)95(F − 32)
    C)59F − 32
    D)59(F + 32)
    Answer: A — Subtract 32 first, then multiply by the reciprocal 5/9.
    • B — multiplied by 9/5 again instead of by its reciprocal
    • C — multiplied only the F by 5/9 — the whole side must be multiplied
    • D — added 32 instead of subtracting it
  8. 1.8
    Make n the subject of Tn = a + (n − 1)d.
    (1)
    A)Tn − ad + 1
    B)Tn − ad
    C)Tn − a + 1d
    D)Tn + ad + 1
    Answer: A — Subtract a, divide by d to reach n − 1, then add 1.
    • B — stopped at n − 1 and never added the 1
    • C — added the 1 inside the fraction instead of after dividing
    • D — added a instead of subtracting it
  9. 1.9
    Make x the subject of xa + xb = 1.
    (1)
    A)aba + b
    B)a + bab
    C)ab
    D)aba − b
    Answer: A — The left side is x(a + b)/(ab), so x = ab/(a + b).
    • B — inverted the fraction at the last step
    • C — multiplied by ab but forgot to divide by (a + b)
    • D — subtracted the denominators instead of adding them when forming the LCD
  10. 1.10
    Make y the subject of 3x − 2y = 12.
    (1)
    A)3x − 122
    B)12 − 3x2
    C)3x + 122
    D)3x − 12
    Answer: A — −2y = 12 − 3x, and dividing by −2 flips both signs to give (3x − 12)/2.
    • B — divided by +2 instead of −2, so both signs came out the wrong way round
    • C — moved the 3x across without changing its sign
    • D — forgot to divide by the 2

Answer grid — marking guideline

1.1ABCD
1.2ABCD
1.3ABCD
1.4ABCD
1.5ABCD
1.6ABCD
1.7ABCD
1.8ABCD
1.9ABCD
1.10ABCD

Question 2

[12 MARKS]
Change the subject of each formula as instructed. Show ALL your steps.
  1. 2.1
    Make x the subject of y = 2x + 6.
    (3)
    y − 6 = 2x  (1)
    x = y − 62  (2)
  2. 2.2
    Make r the subject of V = πr2h, and hence calculate r if V = 500, h = 10 and π ≈ 3,14, correct to TWO decimal places.
    (5)
    r2 = Vπh  (1)
    r = Vπh  (2)
    r = 50031,4  (1) = 3,99  (1)
  3. 2.3
    Make x the subject of ax = bx + c.
    (4)
    ax − bx = c  (1)
    x(a − b) = c  (2)
    x = ca − b  (1)

Question 3

[11 MARKS]
Answer the questions below.
  1. 3.1
    Make n the subject of A = P(1 + in).
    (4)
    AP = 1 + in  (1)
    in = AP − 1  (1)
    n = AP − 1i  (2)
  2. 3.2
    Hence determine how many years it takes R1 000 to grow to R1 400 at 10% p.a. simple interest.
    (4)
    1 4001 000 = 1,4  (1)
    n = 0,40,1  (2) = 4 years  (1)
  3. 3.3
    Explain, in words, the method used when the required letter appears TWICE.
    (3)
    Collect every term containing that letter on one side  (1), factorise the letter out  (1), then divide by the bracket  (1)
TOTAL: 33 marks

This question paper consists of 3 questions.

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