Straight-Line Graphs: Reading y = mx + c — Worksheet & Memo

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Grade 9 · Graphs

Straight-Line Graphs: Reading y = mx + c

MARKING GUIDELINE

Marks

Duration

55 minutes

Questions

Name:

Class:

Date:

Mark

/ 34

Instructions and Information

Answer ALL the questions in this question paper.
Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
Show ALL calculations clearly.
Show all units where applicable.
Number the answers correctly according to the numbering system used in this question paper.
A non-programmable calculator may be used, unless stated otherwise.
Write neatly and legibly.

Question 1

[10 MARKS]

Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.

1.1
For y = 3x + 2, the gradient is …
(1)
A)2
B)3✓
C)3x
D)23
Answer: B — In y = mx + c, m is the gradient.
- A — that is the y-intercept
- C — the gradient is a number, not a term
- D — the two values are not divided
1.2
For y = 4x − 7, the y-intercept is …
(1)
A)4
B)−7✓
C)7
D)1,75
Answer: B — In y = mx + c, c is the y-intercept.
- A — that is the gradient
- C — the sign matters
- D — divided the two values
1.3
The x-intercept of y = 2x − 6 is …
(1)
A)−6
B)3✓
C)6
D)−3
Answer: B — At the x-intercept y = 0, so 2x = 6.
- A — that is the y-intercept
- C — did not divide by 2
- D — got the sign wrong
1.4
A line with a gradient of 0 is …
(1)
A)vertical
B)horizontal✓
C)at 45°
D)impossible
Answer: B — y stays the same for every x.
- A — a vertical line has an UNDEFINED gradient
- C — that is a gradient of 1
- D — y = 5 is a perfectly good line
1.5
The line through (0 ; −4) and (2 ; 0) has a gradient of …
(1)
A)−2
B)2✓
C)12
D)4
Answer: B — m = (0 − (−4)) ÷ (2 − 0) = 2.
- A — subtracted in the wrong order
- C — divided the wrong way round
- D — used only the change in y
1.6
Which line is PARALLEL to y = 3x + 1?
(1)
A)y = −3x + 1
B)y = 3x − 5✓
C)y = 13x
D)y = x + 3
Answer: B — Parallel lines have the SAME gradient.
- A — that gradient is −3
- C — that is the reciprocal, not the same
- D — that gradient is 1
1.7
A line rises from left to right. Its gradient is …
(1)
A)negative
B)positive✓
C)zero
D)undefined
Answer: B — y increases as x increases.
- A — a negative gradient falls from left to right
- C — zero is horizontal
- D — undefined is vertical
1.8
The graph of y = −2x + 6 cuts the x-axis at …
(1)
A)(0 ; 6)
B)(3 ; 0)✓
C)(−3 ; 0)
D)(6 ; 0)
Answer: B — 0 = −2x + 6 gives x = 3.
- A — that is the y-intercept
- C — got the sign wrong
- D — did not divide by 2
1.9
Which equation has a NEGATIVE gradient and a positive y-intercept?
(1)
A)y = 2x + 3
B)y = −2x + 3✓
C)y = 2x − 3
D)y = −2x − 3
Answer: B — m = −2 and c = +3.
- A — that gradient is positive
- C — that y-intercept is negative
- D — both are negative
1.10
The point (2 ; 7) lies on which one of the following lines?
(1)
A)y = 2x + 7
B)y = 3x + 1✓
C)y = x + 7
D)y = 7x + 2
Answer: B — 3(2) + 1 = 7.
- A — gives 11
- C — gives 9
- D — gives 16

Answer grid — marking guideline

1.1	A	B	C	D
1.2	A	B	C	D
1.3	A	B	C	D
1.4	A	B	C	D
1.5	A	B	C	D
1.6	A	B	C	D
1.7	A	B	C	D
1.8	A	B	C	D
1.9	A	B	C	D
1.10	A	B	C	D

Question 2

[12 MARKS]

Answer the questions below on straight-line graphs of the form y = mx + c.

2.1
For y = 3x + 2, write down the gradient and the y-intercept, and hence determine the value of y when x = 4.
(3)
Gradient m = 3 (1)
y-intercept c = 2 (1)
y = 3(4) + 2 = 14 (1)
2.2
Write down the y-intercept of y = 4x − 7, and determine its x-intercept.
(3)
The y-intercept is −7 (1)
At the x-intercept y = 0, so 4x − 7 = 0 (1)
x = 74 = 1,75 (1)
2.3
Determine the x-intercept of y = 2x − 6.
(3)
At the x-intercept y = 0 (1)
2x − 6 = 0 (1)
x = 3 (1)
2.4
Describe what the graph of a line with a gradient of 0 looks like, and write down the equation of the horizontal line through (0 ; 5).
(3)
It is horizontal (1)
y stays the same for every value of x (1)
Its equation is y = 5 (1)

Question 3

[12 MARKS]

The graph of a straight line is drawn below.

3.1
Write down the coordinates of the y-intercept and of the x-intercept, and hence calculate the gradient of the line.
(4)
y-intercept (0 ; −4) (1)
x-intercept (2 ; 0) (1)
m = 0 − (−4)2 − 0 (1)
= 2 (1)
3.2
Determine the gradient of the line.
(3)
m = change in ychange in x = 0 − (−4)2 − 0 (2)
= 2 (1)
3.3
Hence determine the equation of the line in the form y = mx + c.
(3)
m = 2 and c = −4 (2)
y = 2x − 4 (1)
3.4
State whether the gradient is positive or negative, and explain how the graph shows this.
(2)
Positive (1) — the line rises from left to right (reason 1)

TOTAL: 34 marks

This question paper consists of 3 questions.