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Grade 10 · Analytical Geometry
Analytical Geometry: All the Exam Question Types
EXAM-STYLE CLASS TEST
Marks
33
Duration
50 minutes
Questions
3
Name:
Class:
Date:
Mark
/ 33
Instructions and Information
- Answer ALL the questions in this question paper.
- Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
- Show ALL calculations clearly.
- Show all units where applicable.
- Number the answers correctly according to the numbering system used in this question paper.
- A non-programmable calculator may be used, unless stated otherwise.
- Write neatly and legibly.
Question 1
[10 MARKS]Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.
- 1.1The distance between A(1 ; 2) and B(4 ; 6) is …(1)A)5B)7C)25D)2,65
- 1.2The midpoint of P(−2 ; 3) and Q(6 ; −1) is …(1)A)(2 ; 1)B)(4 ; 2)C)(8 ; −4)D)(−4 ; 2)
- 1.3The gradient of the line through (2 ; 5) and (6 ; 13) is …(1)A)2B)12C)−2D)4
- 1.4Two lines are PERPENDICULAR when …(1)A)m1 × m2 = −1B)m1 = m2C)m1 + m2 = 0D)m1 × m2 = 1
- 1.5A line has gradient 3. A line perpendicular to it has gradient …(1)A)−13B)13C)−3D)3
- 1.6A(1 ; 2), B(3 ; 6) and C(5 ; 10) are collinear because …(1)A)mAB = mBC = 2B)AB = BCC)they form a triangleD)AC is the longest of the three lengths
- 1.7The line through (0 ; −3) with gradient 2 has equation …(1)A)y = 2x − 3B)y = 2x + 3C)y = −3x + 2D)y = 3x − 2
- 1.8P(x ; 4) is 5 units from Q(1 ; 0). Then x = …(1)A)4 or −2B)4 onlyC)6 or −4D)3 or −3
- 1.9The distance from the origin to (−6 ; 8) is …(1)A)10B)14C)2D)100
- 1.10Line AB has gradient 4. A line PARALLEL to AB has gradient …(1)A)4B)−14C)−4D)14
Answer grid — circle your answers for Question 1
| 1.1 | A | B | C | D |
| 1.2 | A | B | C | D |
| 1.3 | A | B | C | D |
| 1.4 | A | B | C | D |
| 1.5 | A | B | C | D |
| 1.6 | A | B | C | D |
| 1.7 | A | B | C | D |
| 1.8 | A | B | C | D |
| 1.9 | A | B | C | D |
| 1.10 | A | B | C | D |
Question 2
[11 MARKS]A(2 ; 10) and B(6 ; −2) are two points on the Cartesian plane.
- 2.1Calculate the length of AB. Leave your answer in simplest surd form.(4)
- 2.2Calculate the coordinates of M, the midpoint of AB.(3)
- 2.3Calculate the gradient of AB, and hence write down the gradient of any line perpendicular to AB.(4)
Question 3
[12 MARKS]Answer the questions below.
- 3.1Determine the equation of the line through A(2 ; 10) and B(6 ; −2) in the form y = mx + c.(4)
- 3.2Determine whether the point C(4 ; 4) lies on the line AB. Show your working.(3)
- 3.3Points P(−8 ; 0), Q(−5 ; −8) and R(x ; −14) are collinear. Calculate the value of x.(5)
TOTAL: 33 marks
This question paper consists of 3 questions.