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Grade 8 · Algebraic Expressions · 9 min read

Expanding & Simplifying Algebraic Expressions

Multiplying a monomial into brackets, dividing expressions by a monomial, and substituting values to find the numerical value of an expression — the core Grade 8 algebra skills, with worked examples and a quiz.

"Expanding" means removing brackets by multiplying them out. It is the distributive property from Term 1, now with letters — and it is the skill that everything in Grade 9 algebra is built on.

1Multiplying a monomial by a binomial

x 4 3 3x 12 3(x + 4) = 3x + 12
Expanding as areas: 3(x + 4) is one rectangle split into two, giving 3x + 12.
a(b + c) = ab + ac

The term outside multiplies every term inside the bracket — not just the first one.

Worked ExampleExpand: 3(x + 4)
  1. 1
    Multiply 3 by x: 3 × x = 3x.
    First term inside.
  2. 2
    Multiply 3 by 4: 3 × 4 = 12.
    Second term inside — don't forget it.
  3. 3
    Answer: 3x + 12.
    Write the results with their signs.
Worked ExampleExpand: 2x(3x − 5)
  1. 1
    2x × 3x = 6x2.
    Multiply numbers (2×3=6) and letters (x×x=x2) separately.
  2. 2
    2x × (−5) = −10x.
    Keep the negative sign.
  3. 3
    Answer: 6x2 − 10x.
⚠️

Very common slip: writing 3(x + 4) = 3x + 4. The 3 must reach the 4 as well, giving 3x + 12.

2Expanding then collecting like terms

Worked ExampleExpand and simplify: 2(x + 3) + 4(x − 1)
  1. 1
    Expand each bracket: 2x + 6 and 4x − 4.
    Handle one bracket at a time.
  2. 2
    Write it all out: 2x + 6 + 4x − 4.
  3. 3
    Collect like terms: (2x + 4x) + (6 − 4) = 6x + 2.
    Group x-terms and constants separately.
⚠️

When a minus sits in front of a bracket, it changes every sign inside: 5 − 2(x + 3) = 5 − 2x − 6 = −2x − 1.

3Dividing by a monomial

Worked ExampleSimplify: (12x3 + 8x2) ÷ 4x
  1. 1
    Divide each term separately: 12x3 ÷ 4x and 8x2 ÷ 4x.
    Split the division across the + sign.
  2. 2
    12x3 ÷ 4x = 3x2 (12÷4 = 3, x3÷x = x2).
    Divide the numbers, subtract the exponents.
  3. 3
    8x2 ÷ 4x = 2x.
    8÷4 = 2, x2÷x = x.
  4. 4
    Answer: 3x2 + 2x.

4Substitution — finding the value of an expression

Worked ExampleFind the value of 3x + 2y if x = 4 and y = −1
  1. 1
    Replace the letters with brackets: 3( ) + 2( ).
    Using brackets prevents sign errors.
  2. 2
    3(4) + 2(−1) = 12 + (−2).
    Substitute the given values.
  3. 3
    = 10.
    Adding a negative means subtracting.

Practice exercises

Work each one out, then click to reveal the answer.

  1. 1
    Expand: 5(x + 2)
    Show answer ▾
    5x + 10
  2. 2
    Expand: 4(2a − 3)
    Show answer ▾
    8a − 12
  3. 3
    Expand: 3x(x + 5)
    Show answer ▾
    3x2 + 15x
  4. 4
    Expand: −2(y − 4)
    Show answer ▾
    −2y + 8
  5. 5
    Expand and simplify: 3(x + 2) + 2(x + 1)
    Show answer ▾
    3x+6+2x+2 = 5x + 8
  6. 6
    Expand and simplify: 6 − 3(x − 2)
    Show answer ▾
    6 − 3x + 6 = −3x + 12
  7. 7
    Simplify: (10x2 + 5x) ÷ 5x
    Show answer ▾
    2x + 1
  8. 8
    Find the value of 4a − b if a = 3 and b = 5.
    Show answer ▾
    12 − 5 = 7
🧠

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