Number Patterns: Linear Sequences (Grade 10) — Worksheet & Memo

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Grade 10 · Patterns

Number Patterns: Linear Sequences (Grade 10)

MARKING GUIDELINE

Marks

Duration

50 minutes

Questions

Name:

Class:

Date:

Mark

/ 31

Instructions and Information

Answer ALL the questions in this question paper.
Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
Show ALL calculations clearly.
Show all units where applicable.
Number the answers correctly according to the numbering system used in this question paper.
A non-programmable calculator may be used, unless stated otherwise.
Write neatly and legibly.

Question 1

[10 MARKS]

Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.

1.1
The next term of 5 ; 9 ; 13 ; 17 ; … is …
(1)
A)21✓
B)20
C)22
D)34
Answer: A — The constant difference is 4, so the next term is 17 + 4 = 21.
- B — added 3 instead of the constant difference of 4
- C — added 5, the FIRST term, instead of the difference
- D — doubled 17
1.2
The general term of 5 ; 9 ; 13 ; 17 ; … is …
(1)
A)T_n = 4n + 1✓
B)T_n = 4n
C)T_n = 5n − 1
D)T_n = n + 4
Answer: A — T_n = dn + c with d = 4, and c = 5 − 4 = 1.
- B — left out the constant c — this gives 4, not 5, as the first term
- C — used the FIRST TERM as the coefficient of n instead of the difference
- D — swapped the difference and the constant
1.3
The 20th term of 5 ; 9 ; 13 ; … is …
(1)
A)81✓
B)80
C)85
D)100
Answer: A — T₂₀ = 4(20) + 1 = 81.
- B — used 4n and left out the + 1
- C — added 5 instead of 1
- D — used 5 × 20 instead of 4n + 1
1.4
Which term of 5 ; 9 ; 13 ; … is equal to 101?
(1)
A)the 25th✓
B)the 26th
C)the 20th
D)the 101st
Answer: A — 4n + 1 = 101 gives 4n = 100, so n = 25.
- B — divided 101 by 4 and rounded up, without subtracting the 1 first
- C — divided 101 by 5 instead of using the general term
- D — read the VALUE of the term as its position
1.5
The constant difference of 20 ; 17 ; 14 ; 11 ; … is …
(1)
A)−3✓
B)3
C)−20
D)17
Answer: A — Each term is 3 LESS than the one before, so d = −3.
- B — the sequence decreases, so the difference must be negative
- C — that is the first term with a minus put on it
- D — that is the second term, not the difference
1.6
If T_n = 3n − 7, then the FIRST term is …
(1)
A)−4✓
B)3
C)−7
D)7
Answer: A — T₁ = 3(1) − 7 = −4.
- B — that is the constant difference, not the first term
- C — that is c, which is T₀, not T₁
- D — dropped the minus sign on the 7
1.7
A pattern of figures uses 4, 7, 10 and 13 matchsticks. Its general term is …
(1)
A)T_n = 3n + 1✓
B)T_n = 3n
C)T_n = 4n
D)T_n = n + 3
Answer: A — The difference is 3, and 4 − 3 = 1, so T_n = 3n + 1.
- B — left out the + 1 — this gives 3 for the first figure, not 4
- C — used the FIRST value as the coefficient of n instead of the difference
- D — swapped the difference and the constant
1.8
How many matchsticks does the 50th figure of that pattern need?
(1)
A)151✓
B)150
C)154
D)200
Answer: A — T₅₀ = 3(50) + 1 = 151.
- B — left out the + 1
- C — added 4 instead of 1
- D — used 4 × 50
1.9
A sequence is LINEAR when …
(1)
A)its first difference is constant✓
B)all its terms are positive
C)each term is double the one before
D)its second difference is constant
Answer: A — A constant first difference is exactly what makes the general term dn + c.
- B — the signs of the terms do not decide the type of sequence
- C — that is a GEOMETRIC sequence
- D — a constant SECOND difference gives a QUADRATIC sequence
1.10
For the sequence 2 ; 5 ; 8 ; …, the value of T₁ + T₁₀ is …
(1)
A)31✓
B)29
C)32
D)30
Answer: A — T_n = 3n − 1, so T₁₀ = 29 and 2 + 29 = 31.
- B — gave T₁₀ on its own, without adding T₁
- C — used T₁₀ = 30, forgetting the −1
- D — used 3 × 10 for T₁₀ and left out T₁

Answer grid — marking guideline

1.1	A	B	C	D
1.2	A	B	C	D
1.3	A	B	C	D
1.4	A	B	C	D
1.5	A	B	C	D
1.6	A	B	C	D
1.7	A	B	C	D
1.8	A	B	C	D
1.9	A	B	C	D
1.10	A	B	C	D

Question 2

[12 MARKS]

3x + 1 ; 2x ; 3x − 7 are the first three terms of a LINEAR pattern.

2.1
Calculate the value of x.
(3)
In a linear pattern the first differences are equal (1)
2x − (3x + 1) = (3x − 7) − 2x (1)
−x − 1 = x − 7, so x = 3 (1)
2.2
Determine the numerical value of the first three terms.
(2)
3(3) + 1 = 10; 2(3) = 6; 3(3) − 7 = 2 (1)
10 ; 6 ; 2 (1)
2.3
Determine T_n, the general term of the pattern.
(3)
d = −4 (1)
−4(1) + c = 10, so c = 14 (1)
T_n = −4n + 14 (1)
2.4
Determine which term will be the FIRST to be less than −31.
(4)
−4n + 14 < −31 (1)
−4n < −45 (1)
n > 11,25 — note the sign REVERSES when dividing by −4 (1)
n must be a whole number, so it is the 12th term (T₁₂ = −34) (1)

Question 3

[9 MARKS]

Consider the linear pattern 5 ; 8 ; 11 ; 14 ; …

3.1
Determine the general term T_n.
(3)
d = 3 and T₁ = 5, so c = 2 (2)
T_n = 3n + 2 (1)
3.2
Calculate T₅₀.
(2)
3(50) + 2 (1) = 152 (1)
3.3
Determine whether 100 is a term of this pattern. Justify your answer.
(4)
3n + 2 = 100 (1)
3n = 98 (1)
n = 32,67… (1)
n is not a whole number, so 100 is NOT a term (1)

TOTAL: 31 marks

This question paper consists of 3 questions.