Finding the constant difference, writing the general term Tₙ = dn + c, calculating any term, and working backwards to find which term has a given value.
A sequence is linear (or arithmetic) when you add the same amount each time. That amount is the constant difference, d.
1The general term
Tₙ = dn + c
d = constant difference
c = the term BEFORE the first one (that is, T₀)
d = constant difference
c = the term BEFORE the first one (that is, T₀)
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Because Tₙ = dn + c is the equation of a straight line, the constant difference d is exactly the gradient. That is why the plotted points are collinear.
Worked ExampleDetermine the general term of 5 ; 8 ; 11 ; 14 ; …
- 1d = 8 − 5 = 3. Check: 11 − 8 = 3 and 14 − 11 = 3. ✓Always check the difference is the same all the way.
- 2Tₙ = 3n + c.Substitute d = 3.
- 3T₁ = 5, so 3(1) + c = 5.Use the first term to find c.
- 4c = 2, so Tₙ = 3n + 2.Check T₃: 3(3) + 2 = 11. ✓
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c is not the first term. For 5 ; 8 ; 11 the first term is 5 but c = 2 — it is the value the pattern would have had at n = 0.
2Finding a specific term
Worked ExampleCalculate T₅₀ for the sequence 5 ; 8 ; 11 ; …
- 1Tₙ = 3n + 2.
- 2T₅₀ = 3(50) + 2.Substitute n = 50.
- 3= 152.
3Working backwards
Worked ExampleWhich term of 5 ; 8 ; 11 ; … is equal to 47?
- 13n + 2 = 47.Set the general term equal to the value.
- 23n = 45.
- 3n = 15, so 47 is the 15th term.Check: 3(15) + 2 = 47. ✓
Worked ExampleIs 100 a term of the sequence 5 ; 8 ; 11 ; …?
- 13n + 2 = 100 → 3n = 98.
- 2n = 983 = 32,67…
- 3n is not a whole number, so 100 is not a term of this sequence.Term numbers must be positive integers — say this in words.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Write down the constant difference of 5 ; 8 ; 11 ; 14 ; …
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d = 3 - 2Determine the general term Tₙ of 5 ; 8 ; 11 ; 14 ; …
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d = 3, T₁ = 5 → c = 2 → Tₙ = 3n + 2 - 3Calculate T₅₀ for the sequence 5 ; 8 ; 11 ; …
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3(50) + 2 = 152 - 4Which term of 5 ; 8 ; 11 ; … is equal to 47?
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3n + 2 = 47 → n = 15 - 5Is 100 a term of the sequence 5 ; 8 ; 11 ; …? Justify.
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3n = 98 gives n = 32,67 which is not a whole number, so no. - 6Determine the general term of 7 ; 11 ; 15 ; 19 ; …
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d = 4, c = 3 → Tₙ = 4n + 3 - 7Determine the general term of 20 ; 17 ; 14 ; 11 ; …
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d = −3, c = 23 → Tₙ = −3n + 23 - 8Explain why a linear sequence plots as a straight line.
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Because Tₙ = dn + c is the equation of a straight line, with the constant difference as the gradient.
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