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Grade 9 · Geometry
Pythagoras' Theorem: Finding the Missing Side
EXAM-STYLE CLASS TEST
Marks
39
Duration
1 hour
Questions
4
Name:
Class:
Date:
Mark
/ 39
Instructions and Information
- Answer ALL the questions in this question paper.
- Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
- Show ALL calculations clearly.
- Show all units where applicable.
- Number the answers correctly according to the numbering system used in this question paper.
- A non-programmable calculator may be used, unless stated otherwise.
- Write neatly and legibly.
Question 1
[10 MARKS]Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.
- 1.1In a right-angled triangle, the square on the hypotenuse equals …(1)A)the sum of the other two sidesB)the SUM of the squares on the other two sidesC)the difference of the other two squaresD)twice the area
- 1.2A right-angled triangle has legs of 8 cm and 15 cm. Its hypotenuse is …(1)A)23 cmB)17 cmC)289 cmD)12 cm
- 1.3A ladder 25 m long has its foot 7 m from a wall. It reaches … up the wall.(1)A)18 mB)24 mC)26 mD)32 m
- 1.4Which set of lengths does NOT form a right-angled triangle?(1)A)5 ; 12 ; 13B)9 ; 12 ; 15C)6 ; 8 ; 10D)4 ; 5 ; 6
- 1.5In △PQR, PQ = 9, QR = 12 and PR = 15. The right angle is at …(1)A)PB)QC)RD)there is none
- 1.6To find a SHORTER side of a right-angled triangle, you …(1)A)add the two squaresB)SUBTRACT the squaresC)add the two sidesD)halve the hypotenuse
- 1.7A rectangle is 24 cm by 7 cm. Its DIAGONAL is …(1)A)31 cmB)25 cmC)168 cmD)17 cm
- 1.8A right-angled triangle has legs of 5 cm and 5 cm. Its hypotenuse, in surd form, is …(1)A)10 cmB)50 cmC)25 cmD)25 cm
- 1.9The theorem of Pythagoras can be used to check whether a triangle …(1)A)is isoscelesB)is RIGHT-ANGLEDC)is equilateralD)has equal angles
- 1.10A pole 12 m tall is supported by a wire from its top to a point 5 m from its base. The wire is …(1)A)17 mB)13 mC)7 mD)60 m
Answer grid — circle your answers for Question 1
| 1.1 | A | B | C | D |
| 1.2 | A | B | C | D |
| 1.3 | A | B | C | D |
| 1.4 | A | B | C | D |
| 1.5 | A | B | C | D |
| 1.6 | A | B | C | D |
| 1.7 | A | B | C | D |
| 1.8 | A | B | C | D |
| 1.9 | A | B | C | D |
| 1.10 | A | B | C | D |
Question 2
[10 MARKS]In the diagram below, △PQR has Q̂ = 90°, PQ = 8 cm and QR = 15 cm. S is a point on QR such that QS = 5 cm. The diagram is not drawn to scale.
- 2.1Calculate the length of PR. Give a reason for your statement.(3)
- 2.2Calculate the length of PS, correct to two decimal places.(3)
- 2.3Hence calculate the perimeter of △PSR, correct to one decimal place.(4)
Question 3
[10 MARKS]In the diagram below, ABCD is a quadrilateral with AB = 9 cm, BC = 12 cm, AC = 15 cm, CD = 8 cm and AD = 17 cm. The diagram is not drawn to scale.
- 3.1Show, by calculation, that AB̂C = 90°.(3)
- 3.2Show that △ACD is right-angled and write down which angle is the right angle.(4)
- 3.3Hence calculate the area of quadrilateral ABCD.(3)
Question 4
[9 MARKS]The diagram below shows a closed rectangular box with a length of 12 cm, a breadth of 9 cm and a height of 8 cm. AC is a diagonal of the base and AG is the longest straight rod that will fit inside the box.
- 4.1Calculate the length of the base diagonal AC.(3)
- 4.2Hence calculate the length of AG.(3)
- 4.3A straight metal rod is 16 cm long. Will it fit inside the closed box? Give a reason for your answer.(3)
TOTAL: 39 marks
This question paper consists of 4 questions.