π
∞
∑
∫
θ
E = mc²
y = mx+b
√
Δ
φ
∇
λ
Home›Lessons›Grade 9
Grade 9 · Surface Area and Volume of 3D Objects · 10 min read

Surface Area & Volume of 3-D Objects (Grade 9)

Volume and surface area of cubes, rectangular prisms, triangular prisms and cylinders, SI unit conversions, and what happens to volume when you double the dimensions — with drawn solids, worked examples and a quiz.

Also known as: surface area of a cylinder · volume of a prism

Grade 8 covered cubes, rectangular prisms and triangular prisms. Grade 9 adds the cylinder and takes the triangular prism further — the two shapes that appear most often in real life and in exams.

1The one idea behind every prism

Volume of any prism = area of the cross-section × length

A prism is a solid with the same shape all the way through. Work out the area of that flat cross-section, then multiply by how long the prism is. Every volume formula below is just this idea applied to a different cross-section.

2Rectangular prism (box) and cube

V = l × b × h   ·   Surface area = 2(lb + lh + bh)
Worked ExampleA box measures 6 cm by 4 cm by 3 cm. Find its volume and surface area
6 cm3 cm4 cm
  1. 1
    V = 6 × 4 × 3 = 72 cm³.
    Multiply the three dimensions.
  2. 2
    SA = 2(6 × 4 + 6 × 3 + 4 × 3) = 2(24 + 18 + 12).
    Three pairs of identical faces.
  3. 3
    SA = 2(54) = 108 cm².
    Area is in square units, volume in cubic units.

3Triangular prism

bhℓ
A triangular prism: find the area of the triangular cross-section, then multiply by the length.
Worked ExampleTriangular prism: base 8 cm, height 5 cm, length 10 cm. Find the volume
h = 5 cmb = 8 cmℓ = 10 cm
  1. 1
    Cross-section area = ½ × 8 × 5 = 20 cm².
    Area of the triangle.
  2. 2
    V = 20 × 10.
    Multiply by the length of the prism.
  3. 3
    V = 200 cm³.
Triangular prism
V = area of the triangle × length
SA = 2 × area of the triangle + (perimeter of the triangle) × length

The surface is two identical triangular ends plus three rectangles. Each rectangle is as long as the prism and as wide as one side of the triangle — so adding the three sides FIRST (the perimeter) and multiplying once does all three at a stroke. That means you need all three sides of the triangle, and often one of them has to be found with Pythagoras.

Worked ExampleThe prism below has a right-angled cross-section with sides of 12 cm and 9 cm, and it is 10 cm long. Find its total surface area.
12 cm9 cm?ℓ = 10 cm
  1. 1
    Third side: 122 + 92 = 144 + 81 = 225, so the slanted side is √225 = 15 cm.
    Pythagoras — the perimeter needs all three sides.
  2. 2
    The two triangular ends: 2 × ½ × 12 × 9 = 108 cm2.
    The ends are identical, so work out one and double it.
  3. 3
    The three rectangles: (12 + 9 + 15) × 10 = 36 × 10 = 360 cm2.
    Perimeter of the triangle × length of the prism.
  4. 4
    SA = 108 + 360 = 468 cm2.
    Ends plus sides.
⚠️

Using only the two sides you were given. A triangular prism has three rectangular faces, so the third side of the triangle must be found before you can work out the surface area — even though the volume never needs it.

4Cylinder

A cylinder: the cross-section is a circle of radius r, and the solid is h tall.
V = πr2h   ·   Surface area = 2πr2 + 2πrh

The volume is the circle's area (πr2) times the height. The surface area is the two circular ends (2πr2) plus the curved side, which unrolls into a rectangle of width 2πr and height h.

Worked ExampleA cylinder has radius 5 cm and height 10 cm. Find V and SA (π ≈ 3,14)
r = 5 cmh = 10 cm
  1. 1
    V = πr²h = 3,14 × 5² × 10.
    Square the radius first.
  2. 2
    V = 3,14 × 25 × 10 = 785 cm³.
  3. 3
    SA = 2πr² + 2πrh = 2(3,14)(25) + 2(3,14)(5)(10).
    Two ends plus the curved surface.
  4. 4
    SA = 157 + 314 = 471 cm².
⚠️

Do not confuse πr2 (area of the circular end) with 2πr (its circumference). Squaring the radius is the step learners forget most often.

5SI unit conversions

  • 1 cm3 = 1 mℓ  and  1 000 cm3 = 1 ℓ
  • 1 m3 = 1 000 ℓ = 1 kℓ
  • Area: 1 cm2 = 100 mm2,  1 m2 = 10 000 cm2

6What doubling does to the volume

This is a favourite exam question, and the answer surprises people.

Worked ExampleA cylinder's radius is doubled. What happens to the volume?
rhV = πr²h2rhV = π(2r)²h = 4πr²h→
  1. 1
    Original: V = πr²h.
  2. 2
    New radius 2r: V = π(2r)²h = π(4r²)h.
    Squaring 2r gives 4r² — the 2 gets squared too.
  3. 3
    The volume becomes 4 times as big.
    Doubling the radius multiplies volume by 2² = 4.
  • Double the height only → volume × 2
  • Double the radius only → volume × 4  (because r is squared)
  • Double every dimension → volume × 8

Practice exercises

Work each one out, then click to reveal the answer.

  1. 1
    A cube has a volume of 512 cm3. Determine the length of one edge, and hence the total surface area of the cube.
    Show answer ▾
    edge = ∛512 = 8 cm (2)
    A cube has 6 square faces, so SA = 6 × 82 (1)
    = 384 cm2 (1)
  2. 2
    Volume of a box 6 cm × 4 cm × 3 cm.
    6 cm3 cm4 cm
    Show answer ▾
    72 cm3
  3. 3
    Surface area of a box 6 cm × 4 cm × 3 cm.
    6 cm3 cm4 cm
    Show answer ▾
    2(24 + 18 + 12) = 108 cm2
  4. 4
    Volume of a cube with side 5 cm.
    Show answer ▾
    53 = 125 cm3
  5. 5
    Triangular prism: base 6, height 4, length 12 cm. Find the volume.
    4 cm6 cmℓ = 12 cm
    Show answer ▾
    ½(6)(4) = 12; 12 × 12 = 144 cm3
  6. 6
    The diagram below shows a triangular prism whose cross-section is a right-angled triangle with sides of 15 cm and 8 cm. The prism is 5 cm long. Calculate the length of the third side of the triangle, and then the total surface area of the prism.
    15 cm8 cmℓ = 5 cm
    Show answer ▾
    Third side = √(152 + 82) = √289 = 17 cm (2)
    Two ends = 2 × ½ × 15 × 8 = 120 cm2 (1)
    Three rectangles = (15 + 8 + 17) × 5 = 200 cm2 (1)
    SA = 120 + 200 = 320 cm2 (1)
  7. 7
    Cylinder radius 3 cm, height 7 cm. Find the volume (π ≈ 3,14).
    r = 3 cmh = 7 cm
    Show answer ▾
    3,14 × 9 × 7 = 197,82 cm3
  8. 8
    Cylinder radius 3 cm, height 7 cm. Find the surface area (π ≈ 3,14).
    r = 3 cmh = 7 cm
    Show answer ▾
    2(3,14)(9) + 2(3,14)(3)(7) = 56,52 + 131,88 = 188,4 cm2
  9. 9
    Cylinder radius 2 cm, height 5 cm. Find the volume (π ≈ 3,14).
    r = 2 cmh = 5 cm
    Show answer ▾
    3,14 × 4 × 5 = 62,8 cm3
  10. 10
    How many mℓ does a container of 250 cm3 hold?
    Show answer ▾
    250 mℓ (1 cm3 = 1 mℓ)
  11. 11
    A cylinder's height is doubled. What happens to its volume?
    rhr2h→
    Show answer ▾
    It doubles (height is not squared).
  12. 12
    A cylinder's radius is doubled. What happens to its volume?
    rh2rh→
    Show answer ▾
    It becomes 4 times bigger (r is squared).
🧠

Quick Quiz

5 quick questions on what you just read. Take it when you feel ready.

Now practise it

Download Grade 9 past papers and worksheets on this topic.

Go to Grade 9 papers →