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Grade 12 · Trigonometry
Three-Dimensional Trigonometry (Grade 12)
MEMORANDUM
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Class:
Date:
Mark
/ 16
Answer all questions. Show all your working — marks are awarded for method as well as the final answer. Teacher copy: accept any correct equivalent method.
- 1In the diagram below, calculate the size of DB̂C.(2)180° − 40° − 65° = 75°✓✓ (2)
- 2In the diagram below, calculate the length of BC.(2)BCsin40° = 30sin75° → BC = 19,96 m✓✓ (2)
- 3In the diagram below, calculate the height of the pole AB.(2)AB = BC tan32° = 19,96 × tan32° = 12,47 m✓✓ (2)
- 4Why is AB̂C = 90° in the diagram below?(2)Because AB is vertical and BC lies in the horizontal plane.✓✓ (2)
- 5Which triangle should you solve first in a 3-D problem?(2)The one with the most information — usually the horizontal triangle — so that you can find the shared side.✓✓ (2)
- 6An angle of elevation is measured from which direction?(2)From the horizontal.✓✓ (2)
- 7Calculate the area of △BCD given BC = 19,96 m, CD = 30 m and BĈD = 65°.(2)12(19,96)(30)sin65° = 271,40 m²✓✓ (2)
- 8Can the sine rule be applied to a three-dimensional figure as a whole?(2)No — it applies only within a single plane triangle, so the figure must be split up.✓✓ (2)
TOTAL: 16 marks