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HomeLessonsGrade 10
Grade 10 · Algebraic Expressions · 10 min read

Algebraic Fractions: Simplify, Add & Subtract (Grade 10)

Simplifying algebraic fractions by factorising, multiplying and dividing them, and adding or subtracting using a lowest common denominator — including denominators that factorise as cubes.

Algebraic fractions behave exactly like ordinary fractions. The one extra step is that you must factorise first — nothing can be cancelled until the top and bottom are products.

1Simplifying: factorise, then cancel FACTORS

Worked ExampleSimplify: x2 − 9x + 3
  1. 1
    Factorise the top: x² − 9 = (x − 3)(x + 3).
    A difference of two squares.
  2. 2
    (x − 3)(x + 3)(x + 3)
    Now top and bottom are products.
  3. 3
    Cancel the (x + 3): answer x − 3.
⚠️

You may only cancel factors, never single terms. In x + 33 the 3s do not cancel, because the top is a sum, not a product.

Worked ExampleSimplify: x2 + 5x + 6x2 − 4
  1. 1
    Top: x² + 5x + 6 = (x + 2)(x + 3).
    Trinomial.
  2. 2
    Bottom: x² − 4 = (x − 2)(x + 2).
    Difference of squares.
  3. 3
    Cancel (x + 2): x + 3x − 2

2Multiplying and dividing

Multiply: factorise everything, cancel across, then multiply what is left. Divide: flip the second fraction and multiply.

Worked ExampleSimplify: x2 − 1x ÷ x + 13x
  1. 1
    Flip and multiply: x2 − 1x × 3xx + 1.
    Dividing by a fraction is multiplying by its reciprocal.
  2. 2
    Factorise: x² − 1 = (x − 1)(x + 1).
  3. 3
    Cancel (x + 1) and one x: 3(x − 1).

3Adding and subtracting

1. Factorise every denominatorx² − 1 = (x − 1)(x + 1)2. Build the LCD(x − 1)(x + 1)3. Rewrite each fraction over the LCDmultiply top and bottom by what is missing4. Add the numerators, then simplifykeep the LCD; expand and collect on top
The four steps for adding algebraic fractions. Step 1 is the one learners skip.
Worked ExampleSimplify: 2x + 1 + 3x − 1
  1. 1
    The denominators do not factorise further, so the LCD is (x + 1)(x − 1).
  2. 2
    Rewrite: 2(x − 1)(x + 1)(x − 1) + 3(x + 1)(x + 1)(x − 1).
    Multiply each fraction by what its denominator is missing.
  3. 3
    Top: 2x − 2 + 3x + 3 = 5x + 1.
    Expand and collect.
  4. 4
    = 5x + 1x2 − 1
    The denominator may be left factorised or expanded.
⚠️

When subtracting, the minus applies to the whole numerator. adb + cd = a − b − cd — bracket the second numerator before you subtract.

4When a denominator is a sum or difference of cubes

Worked ExampleSimplify: x − 2x3 − 8
  1. 1
    Factorise the bottom: x³ − 8 = (x − 2)(x² + 2x + 4).
    A difference of two cubes.
  2. 2
    (x − 2)(x − 2)(x2 + 2x + 4)
  3. 3
    Cancel (x − 2): 1x2 + 2x + 4
    The numerator becomes 1, not 0 — a very common slip.
💡

Whenever you see a cube in a denominator, expect it to factorise and cancel. That is exactly why the cube identities are taught just before this topic.

Practice exercises

Work each one out, then click to reveal the answer.

  1. 1
    Simplify: x2 − 16x + 4
    Show answer ▾
    x − 4
  2. 2
    Simplify: x2 − 25x − 5
    Show answer ▾
    x + 5
  3. 3
    Simplify: x2 + 5x + 6x2 − 4
    Show answer ▾
    x + 3x − 2
  4. 4
    Simplify: 6x23x
    Show answer ▾
    2x
  5. 5
    Simplify: x2 − 1x ÷ x + 13x
    Show answer ▾
    3(x − 1)
  6. 6
    Simplify: 1x + 1y
    Show answer ▾
    y + xxy
  7. 7
    Simplify: 2x + 1 + 3x − 1
    Show answer ▾
    5x + 1x2 − 1
  8. 8
    Simplify: x − 2x3 − 8
    Show answer ▾
    1x2 + 2x + 4
  9. 9
    Simplify: x + 3x3 + 27
    Show answer ▾
    1x2 − 3x + 9
🧠

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