Expanding products like (2x + 3)(x² − x + 4) reliably using a grid, then collecting like terms — plus the cube identities that come from it.
Grade 9 multiplied two binomials, giving four products. Grade 10 adds a third term to the second bracket — now there are six, and the usual mistake is simply losing one.
The rule: multiply every term in the first bracket by every term in the second bracket, then collect like terms. A binomial has 2 terms and a trinomial has 3, so there are always 2 × 3 = 6 products before you collect. Count them: if you have only five, one is missing.
1Use a grid so nothing goes missing
- 12x × x² = 2x³; 2x × (−x) = −2x²; 2x × 4 = 8x.First bracket term across the whole second bracket.
- 23 × x² = 3x²; 3 × (−x) = −3x; 3 × 4 = 12.Then the second term.
- 3Collect: 2x³ + (−2 + 3)x² + (8 − 3)x + 12.Group like powers.
- 4= 2x³ + x² + 5x + 12.
Signs travel with their term. In (2x − 3)(x² + x − 5) the second row is −3 times each term, so −3 × (−5) = +15.
2Method 2: one term at a time
Once the grid feels natural, you can skip drawing it: multiply the whole trinomial by the first term of the binomial, then by the second term, and write the two rows one under the other.
- 1x(2x² + 3x − 1) = 2x³ + 3x² − x.First term across the trinomial.
- 2−4(2x² + 3x − 1) = −8x² − 12x + 4.The −4 carries its sign into every product.
- 3Collect: 2x³ + (3 − 8)x² + (−1 − 12)x + 4.Like powers together.
- 4= 2x³ − 5x² − 13x + 4.
x × x² = x³ (add the exponents), not x² and not 2x². With coefficients, multiply the numbers and add the exponents: 2x × 3x² = 6x³.
3Brackets with two variables
- 1a³ + 3a²b − ab²a times each term.
- 2−2a²b − 6ab² + 2b³−2b times each term.
- 3= a³ + a²b − 7ab² + 2b³.a²b and ab² are different terms: only collect terms with the same letters to the same powers.
4Check your answer with a number
Substitute a small value, such as x = 2, into the question and into your answer. For (2x + 3)(x² − x + 4): 7 × 6 = 42. For 2x³ + x² + 5x + 12: 16 + 4 + 10 + 12 = 42. They agree, so the expansion is almost certainly right; if they disagree, look for the slip. Avoid x = 0 and x = 1, which hide mistakes in the powers.
5Exam style: expand and simplify
- 1(x − 1)(x² + x + 1) = x³ + x² + x − x² − x − 1 = x³ − 1.The middle terms cancel.
- 2(x + 2)(x − 3) = x² − x − 6.An ordinary product of binomials.
- 3x³ − 1 − (x² − x − 6) = x³ − 1 − x² + x + 6.Keep the second product in brackets until the minus has changed every sign.
- 4= x³ − x² + x + 5.
6Find one coefficient without expanding everything
Multiple-choice and short questions often ask for just one term of the answer. You do not need all six products: pick out only the pairs whose powers add up to the power you want, and ignore the rest.
- 13x × (−5) = −15x.An x from the first bracket times a constant from the second.
- 2−2 × 4x = −8x.A constant from the first bracket times an x from the second.
- 3−15x − 8x = −23x, so the coefficient is −23.No other pair of terms gives a power of 1.
7Where the cube identities come from
- 1x³ − 2x² + 4x + 2x² − 4x + 8.Six products as usual.
- 2The middle terms cancel in pairs: −2x² + 2x² = 0 and 4x − 4x = 0.This is not a coincidence.
- 3= x³ + 8.A sum of two cubes — this is the identity you will factorise backwards next.
(a − b)(a2 + ab + b2) = a3 − b3
These two identities are why this lesson matters beyond expanding. Read backwards, they are how you factorise a sum or a difference of two cubes later in Grade 10: x³ + 8 = (x + 2)(x² − 2x + 4), exactly the product expanded above.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Expand: (x + 1)(x² + 2x + 3)
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x³ + 3x² + 5x + 3 - 2Expand: (x + 3)(x² − x + 2)
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x³ + 2x² − x + 6 - 3Expand: (2x + 1)(x² + 3x − 2)
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2x³ + 7x² − x − 2 - 4Expand: (x − 2)(x² + 2x + 4)
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x³ − 8 (difference of cubes) - 5Expand: (x + 5)(x² − 5x + 25)
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x³ + 125 - 6Expand: (3x − 1)(x² − x + 2)
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3x³ − 4x² + 7x − 2 - 7How many products before collecting, for a binomial × trinomial?
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Six (2 × 3)
Quick Quiz
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