Every angle relationship a parallel-lines question uses — corresponding, alternate, co-interior, plus straight-line and vertically-opposite angles — with worked examples for finding angles, solving for x, and multi-step reasoning, and a full worksheet.
Also known as: Z-angles · F-angles · C-angles · allied angles · transversal angles
When a straight line (a transversal) crosses two parallel lines, it creates pairs of angles with fixed relationships. In Grade 8–9 geometry the marks come from naming the relationship correctly and quoting the reason. This guide covers every type of question that uses these angles.
1The angle relationships (learn these cold)
- Corresponding angles (same position at each crossing) are EQUAL — 'F' shape. Reason: corresp ∠s; AB ∥ CD.
- Alternate angles (opposite sides of the transversal, between the lines) are EQUAL — 'Z' shape. Reason: alt ∠s; AB ∥ CD.
- Co-interior angles (same side, between the lines) ADD TO 180° — 'C'/'U' shape. Reason: co-int ∠s; AB ∥ CD.
- Also used: angles on a straight line add to 180°, and vertically opposite angles are equal.
2Type 1: Corresponding angles (F shape)
- 1Identify the 'F' shape: same position at each parallel line.That's the corresponding-angles pattern.
- 2Corresponding angles are equal, so the angle is 70°.Reason: corresponding ∠s, parallel lines.
3Type 2: Alternate angles (Z shape)
- 1Spot the 'Z' shape: opposite sides of the transversal, between the lines.That's the alternate-angles pattern.
- 2Alternate angles are equal → 65°.Reason: alternate ∠s, parallel lines.
4Type 3: Co-interior angles (C or U shape)
- 1Spot the 'C'/'U' shape: same side of the transversal, between the lines.Co-interior angles.
- 2They add to 180°, so 180° − 110° = 70°.Reason: co-interior ∠s, parallel lines.
5Type 4: Two-step problems (combine relationships)
- 1Step 1: vertically opposite angles are equal, so this angle is 120°.Reason: vert opp ∠s.
- 2Step 2: its co-interior partner = 180° − 120° = 60°.Reason: co-interior ∠s, parallel lines.
- 3Answer: 60°.Show BOTH steps and BOTH reasons for full marks.
6Type 5: Solving for x (angles given as expressions)
- 1Co-interior angles add to 180°: 2x + (x + 30) = 180.Set up an equation using the relationship.
- 2Simplify: 3x + 30 = 180 → 3x = 150.Collect like terms.
- 3x = 50.Divide by 3. (Check: 2(50)=100 and 50 + 30=80; 100 + 80 = 180 ✓)
- 1Alternate angles are EQUAL: 3x − 10 = x + 40.Equal, not adding to 180 — so make them equal.
- 22x = 50 → x = 25.Solve the linear equation.
Look for the F, Z and C (or U) shapes in the diagram — they instantly tell you which rule applies. Then decide: are the angles EQUAL (F and Z) or do they ADD TO 180° (U)?
These rules only work when the lines are parallel. Check the diagram shows the parallel arrows first. And every angle statement in your answer must carry its reason — that's a separate mark.
Geometry marks are among the most 'gettable' in Grade 8–9 once you know the relationships and always give reasons. Work the worksheet until you can name each one instantly.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Two co-interior angles are (2x)° and (x + 30)°. Determine the value of x, and hence the size of each angle.
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Co-interior angles on parallel lines add up to 180° (1)
3x + 30 = 180 (1)
x = 50 (1)
The angles are 100° and 80° (1) - 2Two corresponding angles are (5x − 18)° and (2x + 30)°. Determine the value of x, and hence the size of each angle.
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Corresponding angles on parallel lines are equal (1)
3x = 48 (1)
x = 16 (1)
The angles are 62° and 62° (1) - 3Two co-interior angles are (3x − 20)° and (x + 40)°. Determine the value of x, and hence the size of each angle.
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Co-interior angles on parallel lines add up to 180° (1)
4x + 20 = 180 (1)
x = 40 (1)
The angles are 100° and 80° (1) - 4In the diagram below, AB ∥ CD. Determine the size of x, giving a reason.
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x = 65° (alt ∠s; AB ∥ CD) - 5In the diagram below, AB ∥ CD. Determine the size of x. Give a reason for your statement.
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x = 48° (corresp ∠s; AB ∥ CD) - 6In the diagram below, AB ∥ CD. Write down the size of x and the reason for your answer.
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x = 180° − 130° = 50° (co-int ∠s; AB ∥ CD) - 7In the diagram below, AB ∥ CD. Determine, with a reason, the size of x.
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x = 180° − 90° = 90° (co-int ∠s; AB ∥ CD) - 8In the diagram below, POQ is a straight line. Determine the size of x.
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x = 180° − 72° = 108° (∠s on a str line) - 9Two straight lines intersect as shown in the diagram below. Determine the size of x.
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x = 115° (vert opp ∠s) - 10In the diagram below, AB ∥ CD. Determine the sizes of y and then x, giving reasons.
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y = 100° (corresp ∠s; AB ∥ CD), then x = 180° − 100° = 80° (co-int ∠s; AB ∥ CD) - 11In the diagram below, AB ∥ CD. Calculate the value of x.
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3x + 60 = 180 → 3x = 120 → x = 40 - 12In the diagram below, AB ∥ CD. Solve for x.
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4x = x + 45 → 3x = 45 → x = 15 - 13In the diagram below, AB ∥ CD. Determine the value of x.
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5x − 20 = 3x + 10 → 2x = 30 → x = 15
Quick Quiz
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