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Grade 12 · Probability
Counting Principles & Probability (Grade 12)
EXAM-STYLE CLASS TEST
Marks
33
Duration
50 minutes
Questions
3
Name:
Class:
Date:
Mark
/ 33
Instructions and Information
- Answer ALL the questions in this question paper.
- Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
- Show ALL calculations clearly.
- Show all units where applicable.
- Number the answers correctly according to the numbering system used in this question paper.
- A non-programmable calculator may be used, unless stated otherwise.
- Write neatly and legibly.
Question 1
[10 MARKS]Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.
- 1.1The number of ways to arrange 5 different books in a row is …(1)A)120B)25C)5D)10
- 1.2The FUNDAMENTAL COUNTING PRINCIPLE says the total number of ways is found by …(1)A)multiplying the number of choices at each stageB)adding the number of choices at each stageC)taking the largest number of choicesD)taking the factorial of the number of stages
- 1.3A PIN has 4 digits, each from 0 to 9, and repeats ARE allowed. The number of possible PINs is …(1)A)10 000B)5 040C)40D)24
- 1.4If repeats are NOT allowed, the number of 4-digit PINs is …(1)A)5 040B)10 000C)24D)40
- 1.5The number of ways to arrange the letters of the word LEVEL is …(1)A)30B)120C)60D)20
- 1.6Five people sit in a row, but two particular people must sit TOGETHER. The number of arrangements is …(1)A)48B)120C)24D)240
- 1.7Four letters are arranged at random. The probability of one particular arrangement is …(1)A)124B)14C)116D)112
- 1.8Three coins are tossed and a die is rolled. The sample space has …(1)A)48 outcomesB)18 outcomesC)12 outcomesD)36 outcomes
- 1.9In how many ways can a chairperson and a secretary be chosen from 8 people?(1)A)56B)64C)28D)40 320
- 1.10Two events are INDEPENDENT when …(1)A)P(A and B) = P(A) × P(B)B)P(A and B) = 0C)P(A or B) = P(A) + P(B)D)P(A) = P(B)
Answer grid — circle your answers for Question 1
| 1.1 | A | B | C | D |
| 1.2 | A | B | C | D |
| 1.3 | A | B | C | D |
| 1.4 | A | B | C | D |
| 1.5 | A | B | C | D |
| 1.6 | A | B | C | D |
| 1.7 | A | B | C | D |
| 1.8 | A | B | C | D |
| 1.9 | A | B | C | D |
| 1.10 | A | B | C | D |
Question 2
[11 MARKS]The letters of the word NUMBERS are arranged in a row. The word has 7 different letters.
- 2.1Determine the number of different arrangements possible, and how many of them begin with the letter N.(3)
- 2.2Determine the number of arrangements in which the letters N and U are next to each other.(4)
- 2.3Hence determine the probability that in a random arrangement N and U are NOT next to each other.(4)
Question 3
[12 MARKS]A code consists of 4 digits chosen from 0 to 9.
- 3.1Determine how many codes are possible if digits may be repeated, and how many of those begin with an EVEN digit.(3)
- 3.2Determine how many codes are possible if no digit may be repeated.(3)
- 3.3Determine the probability that a randomly chosen 4-digit code has no repeated digit.(3)
- 3.4Explain why the answer to the previous part would be smaller for a 5-digit code, and calculate that probability.(3)
TOTAL: 33 marks
This question paper consists of 3 questions.