Sketching y = a/x and y = abx, finding asymptotes and intercepts, and reading the effect of a, b and a vertical shift q — the two curved graphs of Grade 10.
Also known as: reciprocal graphs · asymptotes · exponential growth
Grade 10 adds two curves to the straight line and the parabola. Both are sketched the same way: find the asymptotes, find any intercepts, plot one or two points, then draw the shape.
1The hyperbola: y = a/x
vertical asymptote x = 0 · horizontal asymptote y = q
- An asymptote is a line the curve gets closer and closer to as it runs out to the side or up and down. The hyperbola and the exponential graph in this lesson never cross theirs.
- For the PARENT graph y = a/x (that is, q = 0): if a > 0 the branches sit in quadrants 1 and 3; if a < 0 they sit in quadrants 2 and 4. Adding q slides the whole graph up or down, so a shifted hyperbola can reach into other quadrants.
- There is no y-intercept — x can never be 0, because you cannot divide by zero.
- 1Asymptotes: x = 0 and y = 0.The standard hyperbola has the axes as its asymptotes.
- 2a = 6 > 0, so the branches are in quadrants 1 and 3.
- 3Plot a few points: (1 ; 6), (2 ; 3), (6 ; 1) — and (−1 ; −6), (−2 ; −3).Pick x-values that divide into 6 neatly.
- 4Draw two smooth branches approaching the axes.Never let the curve touch an asymptote.
- 1Vertical asymptote: x = 0.Unchanged — the denominator is still x.
- 2Horizontal asymptote: y = −3.The whole graph has shifted down 3, so q = −3.
A hyperbola never has a y-intercept, and y = a/x + q never reaches y = q. If your sketch touches an asymptote, it is wrong.
2The exponential graph: y = abx
horizontal asymptote y = q · y-intercept at x = 0
- With a > 0: if b > 1 the graph increases (growth); if 0 < b < 1 it decreases (decay). A negative a flips the curve over its asymptote, so each case does the opposite. The base itself is always b > 0, b ≠ 1.
- There is one horizontal asymptote, y = q. Whether there is an x-intercept depends on a, b and q: solve a·bx + q = 0. y = 3·2x − 4 does cut the x-axis; y = 3·2x + 4 never does, because 3·2x is always positive.
- Every exponential graph of the form y = bx passes through (0 ; 1), because b0 = 1.
- 1Asymptote: y = 0.q = 0, so the x-axis.
- 2y-intercept: 20 = 1, giving (0 ; 1).Every such graph passes through (0 ; 1).
- 3Points: (1 ; 2), (2 ; 4), (3 ; 8); and (−1;½), (−2;¼).Negative x gives small positive values — never negative.
- 4Draw a smooth curve rising to the right, flattening left towards y = 0.
- 1Asymptote: y = −4.q = −4.
- 2y-intercept: let x = 0 → y = 3(1) − 4 = −1.b0 = 1, so the a value shows through.
- 3y-intercept is (0 ; −1).
For any graph: the y-intercept comes from letting x = 0, and the x-intercept from letting y = 0. That one rule covers all four Grade 10 functions.
Practice exercises
Work each one out, then click to reveal the answer.
- 1What are the asymptotes of y = 6/x?
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x = 0 and y = 0 - 2What are the asymptotes of y = 4/x − 3?
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x = 0 and y = −3 - 3In which quadrants does y = 6/x lie?
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1 and 3 (since a > 0) - 4In which quadrants does y = −5/x lie?
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2 and 4 (since a < 0) - 5Why does a hyperbola have no y-intercept?
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x cannot be 0 — you cannot divide by zero. - 6Find y when x = 3 for y = 6/x.
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y = 2 - 7What is the y-intercept of y = 2x?
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(0 ; 1) - 8What is the asymptote of y = 2x + 5?
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y = 5 - 9Find the y-intercept of y = 3·2x − 4.
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y = 3(1) − 4 = −1, so the intercept is (0 ; −1) - 10Does y = (½)x increase or decrease?
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Decreases — the base is between 0 and 1.
Quick Quiz
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