Logs as the reverse of exponents — evaluating, converting between log and exponent form, solving for an unknown exponent such as the n in a finance question, and the graph of y = logb x as the inverse of y = bx — each worked in full, with the log laws as enrichment and a worksheet.
A logarithm answers one question: 'what power do I raise the base to, to get this number?' It's the exact reverse of an exponent — that single idea makes logs easy.
for b > 0, b ≠ 1 and y > 0
The conditions that come with it: the base must be positive and not 1 (b > 0, b ≠ 1), and you may only take the log of a POSITIVE number (y > 0). That is why log 0 and log(−5) do not exist, and why a log equation's answers must always be checked against the original expression.
Read log2 8 as 'the power that turns 2 into 8'. Since 23 = 8, log2 8 = 3.
1Type 1: Evaluate a logarithm
- 1Ask: 5 to what power gives 125?The meaning of the log.
- 253 = 125.5 × 5 × 5 = 125.
- 3So log₅ 125 = 3.The logarithm is the exponent.
2Type 2: Convert between log and exponent form
- 124 = 16 → log₂ 16 = 4.Base stays the base; the exponent becomes the log's value.
- 2log₃ 81 = 4 → 34 = 81.Reverse the same relationship.
3Beyond the ATP (not examined): the log laws
The Grade 12 ATP examines the definition of a logarithm, its graph and its use in finding n; it does not examine the log laws or change of base. They are here because they explain how a calculator evaluates logs — read them, but do not expect them in the exam.
- 1Product law: log 4 + log 25 = log(4 × 25) = log 100.Adding logs → multiply the numbers.
- 2log₁₀ 100 = 2.102 = 100.
4Beyond the ATP (not examined): change of base
The Casio fx-82ZA PLUS used in South African schools has a log□ key for any base. On a calculator with only log (base 10) and ln keys, use the change-of-base rule: logb y = (log y)/(log b).
- 1log₂ 20 = log 20 ÷ log 2.Change-of-base rule (any base on the calculator).
- 2≈ 1,301 ÷ 0,301 ≈ 4,32.Use the log button.
5Type 3: Solve for an unknown exponent
- 1Write it in log form: x = log3 40.By definition, 3x = 40 means x is the power that turns 3 into 40.
- 2Evaluate on the calculator with the log□ key: x ≈ 3,36.Check: 33,36 ≈ 40 ✓
Logs let you solve for an unknown in the exponent — e.g. 'how long until an investment doubles?' Write the equation in log form and evaluate it. Logs are also the inverse of the exponential graph.
log(a + b) is NOT log a + log b. The laws work on products and quotients — log(ab) = log a + log b — never on sums. One of the most common log errors.
Logs appear in finance, functions and exponential equations across matric. Master these five types in the worksheet.
6The graph when the base is between 0 and 1
If b > 1 the log graph increases. If 0 < b < 1 it decreases — it is the first graph reflected in the x-axis. Either way the domain is x > 0, the range is y ∈ ℝ, and the y-axis is a vertical asymptote.
log½ 8 = −3, not 3. A base below 1 gives negative outputs for x > 1 — check the sign against the graph before you write it down.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Evaluate log₂ 16. (evaluate)
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24 = 16 → 4 - 2Evaluate log₃ 27. (evaluate)
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33 = 27 → 3 - 3Evaluate log₁₀ 1 000. (evaluate)
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103 = 1000 → 3 - 4Write 53 = 125 in log form. (convert)
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log₅ 125 = 3 - 5Write log₂ 32 = 5 in exponent form. (convert)
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25 = 32 - 6Solve log₂ x = 5. (definition)
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x = 25 (1)
x = 32 (1) - 7Write down the inverse of f(x) = 3x in the form y = … (inverse)
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swap x and y: x = 3y (1)
y = log₃ x (1) - 8State the domain and the range of y = log₂ x. (graph)
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domain: x > 0 (1)
range: y ∈ ℝ (1) - 9Money invested at 8% p.a. compound interest doubles after n years. Find n (2 dp). (finance)
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2 = (1,08)n (1)
n = log1,08 2 ≈ 9,01 years (1) - 10Solve 2x = 20 (2 dp). (solve)
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x = log₂ 20 (2)
x ≈ 4,32 (1)
Quick Quiz
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