The line joining the midpoints of two sides of a triangle is parallel to the third side and half its length — the theorem, its converse, and how to use each in a proof.
This is one of the most useful results in Grade 10 geometry, and it is short enough to learn word for word.
1The theorem
DE ∥ BC and DE = ½BC
Say it as one sentence: "the line joining the midpoints of two sides of a triangle is parallel to the third side and equal to half of it." That exact wording is the reason you quote in a proof.
2Using it to find a length
- 1DE = ½BC (midpoint theorem)Quote the theorem as your reason.
- 2DE = ½ × 14.
- 3DE = 7 cm.
- 1DE = ½BC, so BC = 2 × DE.Working backwards, double it.
- 2BC = 13 cm.
3The converse
The theorem also works in reverse, and the converse is examined just as often.
then it bisects the third side.
- 1Statement: D is the midpoint of AB (given)
- 2Statement: DE ∥ BC (given)
- 3∴ AE = EC, so E is the midpoint of AC (converse of the midpoint theorem)Name the converse explicitly — that is what earns the reason mark.
The theorem needs two midpoints; the converse needs one midpoint plus a parallel line. Check which one you have been given before quoting a reason.
4Why it works
△ADE and △ABC share the angle at A, and AD : AB = AE : AC = 1 : 2. The triangles are therefore similar, so every side of △ADE is half the matching side of △ABC — which gives DE = ½BC — and the equal corresponding angles make DE ∥ BC.
Practice exercises
Work each one out, then click to reveal the answer.
- 1State the midpoint theorem.
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The line joining the midpoints of two sides of a triangle is parallel to the third side and half its length. - 2D and E are midpoints of AB and AC; BC = 14 cm. Find DE.
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7 cm - 3D and E are midpoints of AB and AC; BC = 25 cm. Find DE.
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12,5 cm - 4D and E are midpoints; DE = 6,5 cm. Find BC.
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13 cm - 5D and E are midpoints; DE = 9 cm. Find BC.
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18 cm - 6State the converse of the midpoint theorem.
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A line through the midpoint of one side, parallel to a second side, bisects the third side. - 7D is the midpoint of AB and DE ∥ BC. What can you conclude about E?
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E is the midpoint of AC (converse of the midpoint theorem). - 8Why are △ADE and △ABC similar?
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They share ∠A and AD:AB = AE:AC = 1:2.
Quick Quiz
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