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Grade 11 · Trigonometry
Trig Equations & General Solutions (Grade 11)
MEMORANDUM
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Mark
  / 22

Answer all questions. Show all your working — marks are awarded for method as well as the final answer. Teacher copy: accept any correct equivalent method.

  1. 1
    Determine the general solution of sinθ = 0,5
    (3)
    θ = 30° + k·360° or θ = 150° + k·360°, k ∈ ℤ✓✓✓ (3)
  2. 2
    Determine the general solution of cosθ = −0,5
    (3)
    ref = 60°, cos negative in QII and QIII →θ = ±120° + k·360°, k ∈ ℤ✓✓✓ (3)
  3. 3
    Determine the general solution of tanθ = √3
    (2)
    θ = 60° + k·180°, k ∈ ℤ✓✓ (2)
  4. 4
    Solve sinθ = 0,5 for θ ∈ [0° ; 360°]
    (2)
    θ = 30° or θ = 150°✓✓ (2)
  5. 5
    Solve cosθ = 0,7660 for θ ∈ [0° ; 360°] (round to one decimal)
    (3)
    ref = 40,0° → θ = 40,0° or θ = 320,0°✓✓✓ (3)
  6. 6
    Determine the general solution of tan(2x − 30°) = 1
    (3)
    2x − 30° = 45° + k·180° → x = 37,5° + k·90°, k ∈ ℤ✓✓✓ (3)
  7. 7
    State the reference angle for sinθ = 0,8660.
    (1)
    ref = sin−1(0,8660) = 60° (to the nearest degree)✓ (1)
  8. 8
    Determine the general solution of sin 2θ = cosθ.
    (4)
    cosθ = sin(90° − θ), so sin 2θ = sin(90° − θ)  (1)
    2θ = 90° − θ + k·360° ⇒ 3θ = 90° + k·360° ⇒ θ = 30° + k·120°  (1)
    or 2θ = 180° − (90° − θ) + k·360° ⇒ θ = 90° + k·360°  (1)
    θ = 30° + k·120° or θ = 90° + k·360°, k ∈ ℤ  (1)
    ✓✓✓✓ (4)
  9. 9
    Why must k ∈ ℤ be written down?
    (1)
    It states that the pattern repeats for every integer k — without it the solution is incomplete and loses a mark.✓ (1)
TOTAL: 22 marks
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