The shapes of y = sin x, y = cos x and y = tan x on [0° ; 360°], and what a and q do in y = a sin x + q — amplitude, vertical shift, range and asymptotes.
1The two wave graphs
- y = sin x starts at 0, peaks at 90°, back to 0 at 180°, minimum at 270°.
- y = cos x starts at 1, crosses at 90°, minimum at 180°, back to 1 at 360°.
- Both have amplitude 1, period 360° and range −1 ≤ y ≤ 1.
cos is just sin shifted 90° to the left. If you can draw one you can draw the other.
2The effect of a — amplitude
A negative a flips the graph in the x-axis. y = −sin x starts by going down instead of up.
3The effect of q — vertical shift
- 1Amplitude = |2| = 2.
- 2Period = 360°.Grade 10 does not change the period — that is Grade 11.
- 3Range: 1 − 2 ≤ y ≤ 1 + 2.Centre line is y = q = 1, reaching 2 either side.
- 4−1 ≤ y ≤ 3.
The maximum of y = 2 sin x + 1 is 3, not 2. Work out the amplitude and the shift separately, then combine.
4The tangent graph
tan has no amplitude (it has no maximum or minimum), a period of 180°, and vertical asymptotes wherever cos x = 0 — at 90° and 270° in this interval.
Draw the asymptotes as dashed lines before you draw the curve. Marks are awarded for them, and the shape becomes obvious once they are there.
5Working backwards: finding the equation of a given graph
Sketching a graph from an equation is half the skill. The ATP also asks you to find the equation of a given graph, and papers ask it constantly. Read off three things, in this order.
- Which curve is it? A sine graph starts at its middle value and rises; a cosine graph starts at a maximum or minimum; a tangent graph has asymptotes.
- q — the vertical shift. q = (maximum + minimum) ÷ 2. That is the value the curve oscillates about.
- a — the amplitude. a = (maximum − minimum) ÷ 2. If the curve is flipped (a sine graph that goes down first), a is negative.
- 1q = (5 + (−1))/2 = 2The centre line of the curve.
- 2a = (5 − (−1))/2 = 3Half the total vertical spread.
- 3The graph starts at its maximum, so a is positive.A negative a would flip it to start at the minimum.
- 4y = 3 cos θ + 2
- 1max = 2 and min = −4Read straight off the range.
- 2q = (2 + (−4))/2 = −1
- 3a = (2 − (−4))/2 = 3, but the graph FALLS first, so a = −3A normal sine graph rises from its centre line. Falling means it is reflected.
- 4y = −3 sin θ − 1
Reading the amplitude as the maximum. For y = 3 cosθ + 2 the maximum is 5, not 3. Amplitude is the distance from the centre line to the maximum — and the centre line is only the θ-axis when q = 0.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Write down the amplitude of y = 2 sin x.
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2 - 2Write down the period of y = sin x.
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360° - 3Write down the range of y = 2 sin x + 1.
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−1 ≤ y ≤ 3 - 4Describe the transformation from y = cos x to y = cos x + 1.
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A shift of 1 unit upwards - 5Write down the equations of the asymptotes of y = tan x for x ∈ [0° ; 360°].
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x = 90° and x = 270° - 6Write down the maximum value of y = 3 cos x − 1.
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3 − 1 = 2 - 7For what value of x in [0° ; 360°] does y = sin x reach its minimum?
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x = 270° - 8What does a negative value of a do to y = a sin x?
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It reflects the graph in the x-axis. - 9The graph of y = a sinθ + q, where a > 0, has a maximum value of 7 and a minimum value of 1. Determine the values of a and q, and write down the equation of the graph.
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q = (7 + 1)/2 = 4 ✓; a = (7 − 1)/2 = 3 ✓; y = 3 sinθ + 4 ✓ - 10The graph of y = a cosθ + q, where a > 0, has a range of [−5 ; 3]. Determine a and q.
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q = (3 + (−5))/2 = −1 ✓; a = (3 − (−5))/2 = 4 ✓; so y = 4 cosθ − 1 ✓ - 11A cosine graph passes through a MINIMUM at θ = 0° and has amplitude 2 with no vertical shift. Write down its equation and explain the sign of a.
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y = −2 cosθ ✓✓; a is negative because an ordinary cosine graph starts at a maximum — starting at a minimum means it has been reflected in the θ-axis ✓
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