The question that carries the most marks in Paper 2 — finding angles with reasons and proving results. The statement-and-reason discipline, every reason a Grade 10 may quote, how to read a diagram before you write anything, and four full riders worked from first line to conclusion.
Also known as: riders · geometry proofs · prove with reasons · statement and reason · Euclidean geometry grade 10
A rider is a geometry question that gives you a diagram and asks you to work something out — or prove something — by applying theorems one after another. In a paper it looks like “Determine, with reasons, the size of x” or “Prove that ABCD is a parallelogram”.
Riders carry more marks than any other part of Paper 2, and they are where most marks are lost — not because learners cannot see the answer, but because they cannot justify it. This lesson is about the justification.
1The one rule that decides your mark
Every statement you write needs a reason. A correct angle with no reason earns the statement mark and loses the reason mark — usually half the question.
Write it as a two-part line, every time:
- AD̂E = 70° (corresponding ∠s; DE ∥ BC) — correct, both marks.
- AD̂E = 70° — correct answer, half the marks.
- AD̂E = 70° (they look the same) — no reason mark. Measuring or eyeballing is never a reason.
The most expensive habit in Grade 10 geometry is doing the whole rider correctly in your head and writing only the answers. The marking guideline pays for the reasoning chain. If a marker cannot follow how you got from the given information to the answer, the marks are not there to give.
2The reasons you may quote in Grade 10
You may only use a result that has been proved. These are the ones available to you, with the exact wording to write in brackets:
- Lines: ∠s on a str line (add to 180°) · ∠s round a pt (360°) · vert opp ∠s
- Parallel lines: corresp ∠s; AB ∥ CD · alt ∠s; AB ∥ CD · co-int ∠s; AB ∥ CD (add to 180°)
- Triangles: ∠s of a △ (add to 180°) · ext ∠ of a △ · ∠s opp equal sides · sides opp equal ∠s · Pythagoras
- Congruence: SSS · SAS · AAS · RHS — then △ABC ≡ △PQR, and matching parts follow by ≡△s
- Similarity: AAA (equiangular) · sides in proportion — then △ABC ||| △PQR
- Quadrilaterals: opp sides of a parm · opp ∠s of a parm · diags of a parm · the five tests for proving a parallelogram
- Midpoint theorem: the line joining the midpoints of two sides is parallel to the third side and half its length — and its converse
Markers accept the standard abbreviations, and they are much faster to write. Learn them now: corresp ∠s, alt ∠s, co-int ∠s, vert opp ∠s, ∠s of a △, ext ∠ of a △. When you quote a parallel-line reason you must also name the parallel lines — “corresp ∠s” alone is incomplete.
3How to attack a rider
- Mark the diagram. Write every given size onto it. Put arrows on parallel lines and ticks on equal sides. A rider you have marked up is half solved.
- Find what you are asked for and look at what touches it. Which angle sits on a straight line with it? Which triangle is it inside?
- Work from the given, not from the answer. Start at a size you know and take one justified step at a time.
- Never assume what the diagram looks like. Lines that appear equal, parallel or perpendicular are not, unless you are told or you prove it.
- Use your earlier answers. A rider is built in parts on purpose — 4.1 is nearly always the way into 4.2.
4Rider 1 — angles with reasons
- 1AD̂E = 70°corresp ∠s; DE ∥ BC
- 2Ĉ = 180° − 50° − 70° = 60°∠s of a △
- 3Check: AÊD = 60° (corresp ∠s; DE ∥ BC), and 50° + 70° + 60° = 180° ✓A quick check inside the small triangle catches an arithmetic slip.
Notice how short the working is once the reasons are in place. That is what a full-mark rider looks like — not more writing, the right writing.
5Rider 2 — using congruence
- 1AB = DCopp sides of a parm
- 2BC = ADopp sides of a parm
- 3AC = CAcommon side — the step learners forget
- 4∴ △ABC ≡ △CDASSS
- 5It follows that AB̂C = AD̂C.≡△s — matching angles of congruent triangles are equal
Writing the vertices in the wrong order. △ABC ≡ △CDA says A matches C, B matches D and C matches A. If you write △ABC ≡ △ACD you have claimed a different pairing, and every conclusion you draw from it is wrong. Match the letters to the equal parts, in order.
6Rider 3 — proving a quadrilateral is a parallelogram
There are five accepted ways. You need one of them, proved — not asserted:
- Both pairs of opposite sides are parallel.
- Both pairs of opposite sides are equal.
- Both pairs of opposite angles are equal.
- One pair of opposite sides is both equal AND parallel.
- The diagonals bisect each other.
- 1PQ ∥ SRgiven
- 2PQ = SRgiven
- 3∴ PQRS is a parallelogramone pair of opp sides equal and parallel
The fourth test is the one examiners reach for most, because it needs the least information. If a question hands you one pair of sides that is both equal and parallel, that is almost certainly the route they intend.
Using a property of a parallelogram to prove the shape is one. You cannot write “opp sides of a parm” as a reason in a proof whose conclusion is that the shape is a parallelogram — that assumes what you are asked to prove. Properties are what you get after the shape is established.
7Rider 4 — the midpoint theorem
The midpoint theorem gives you two conclusions from one condition, and a rider will usually want both.
- 1DE = ½ × 18 = 9 cmmidpt theorem
- 2DE ∥ BCmidpt theorem
- 3AD̂E = 64°corresp ∠s; DE ∥ BC
The converse is examined too, and it works the other way: if a line through the midpoint of one side is parallel to a second side, then it bisects the third side. Use it when you are given a midpoint and a parallel line, and asked to prove something is a midpoint.
8What a full-mark answer looks like
- One statement per line, with its reason in brackets on the same line.
- Every parallel-line reason names the parallel lines.
- Congruent triangles written with matching vertices in order.
- The final line answers the question that was actually asked, in the units asked for.
- Nothing assumed from the look of the diagram.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Write down the reason you would quote for the statement “x = 65°” if the two angles are on opposite sides of a transversal, between two parallel lines AB and CD.
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alt ∠s; AB ∥ CD - 2Why is a correct angle written with no reason usually worth only half the marks?
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The marking guideline awards a mark for the statement and a separate mark for the reason; without the reason the second mark cannot be given. ✓✓ - 3In △PQR, ST ∥ QR with S on PQ and T on PR. P̂ = 44° and Q̂ = 76°. Determine, with reasons, the size of PŜT.
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PŜT = 76° ✓ (corresp ∠s; ST ∥ QR) ✓✓ - 4Using the same triangle, determine, with a reason, the size of R̂.
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R̂ = 180° − 44° − 76° ✓ = 60° ✓ (∠s of a △) ✓ - 5List the FOUR conditions for congruency and state which one applies only to right-angled triangles.
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SSS, SAS, AAS and RHS ✓✓✓; RHS applies only to right-angled triangles ✓ - 6ABCD is a parallelogram with diagonal BD drawn. Prove that △ABD ≡ △CDB.
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AB = CD ✓ (opp sides of a parm); AD = CB ✓ (opp sides of a parm); BD = DB ✓ (common); ∴ △ABD ≡ △CDB ✓ (SSS) - 7State THREE different ways of proving that a quadrilateral is a parallelogram.
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Any three of: both pairs of opp sides parallel ✓; both pairs of opp sides equal ✓; both pairs of opp ∠s equal ✓; one pair of opp sides equal and parallel; diagonals bisect each other - 8In △ABC, D and E are the midpoints of AB and AC. If DE = 7,5 cm and AĈB = 58°, determine BC and AÊD, with reasons.
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BC = 2 × 7,5 = 15 cm ✓✓ (midpt theorem); AÊD = 58° ✓ (corresp ∠s; DE ∥ BC) ✓ - 9Explain why you may NOT use the reason “opp sides of a parm” inside a proof whose conclusion is that the shape is a parallelogram.
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It assumes the very thing you are asked to prove ✓. Properties of a parallelogram may only be used once the shape has been established as one ✓. - 10PQRS is a quadrilateral with PQ ∥ SR and PQ = SR. Prove that PQRS is a parallelogram.
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PQ ∥ SR ✓ (given); PQ = SR ✓ (given); ∴ PQRS is a parallelogram ✓ (one pair of opp sides equal and parallel)
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