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Grade 11 · Trigonometry
Sine, Cosine & Area Rules (Grade 11)
MEMORANDUM
Name:
Class:
Date:
Mark
/ 16
Answer all questions. Show all your working — marks are awarded for method as well as the final answer. Teacher copy: accept any correct equivalent method.
- 1In △ABC, Â = 40°, B̂ = 75° and AC = 12 units. Calculate the length of BC.(2)BCsin40° = 12sin75° → BC = 7,99 units✓✓ (2)
- 2In △ABC, AC = 8 units, AB = 5 units and  = 60°. Calculate the length of BC.(2)BC² = 64 + 25 − 80cos60° = 49 → BC = 7 units✓✓ (2)
- 3Calculate the area of △ABC if AC = 8 units, AB = 5 units and  = 60°.(2)12(8)(5)sin60° = 17,32 square units✓✓ (2)
- 4Which rule would you use given three sides and no angles?(2)The cosine rule, rearranged as cos A = b² + c² − a²2bc✓✓ (2)
- 5Which rule would you use given two angles and one side?(2)The sine rule✓✓ (2)
- 6Write down the area rule for △PQR using sides p and q.(2)Area = 12·pq·sin R✓✓ (2)
- 7In △ABC, a = 7, b = 8, c = 5. Calculate  to one decimal.(2)cos A = 64 + 25 − 492(8)(5) = 4080 = 0,5 →  = 60,0°✓✓ (2)
- 8Why can SOHCAHTOA not be used in △ABC above?(2)It is not right-angled — SOHCAHTOA is only defined for right-angled triangles.✓✓ (2)
TOTAL: 16 marks