∑ DANEMATHICS
FREE CAPS MATHS RESOURCES
Grade 11 · Trigonometry
Sine, Cosine & Area Rules (Grade 11)
EXAM-STYLE CLASS TEST
Marks
50
Duration
1 hour 15 minutes
Questions
4
Name:
Class:
Date:
Mark
/ 50
Instructions and Information
- Answer ALL the questions in this question paper.
- Answer QUESTION 1 by circling the letter (A–D) in the answer grid at the end of that section.
- Show ALL calculations clearly.
- Show all units where applicable.
- Number the answers correctly according to the numbering system used in this question paper.
- A non-programmable calculator may be used, unless stated otherwise.
- Write neatly and legibly.
Question 1
[10 MARKS]Four options are given as possible answers to the following questions. Choose the correct answer and circle the letter (A–D) in the grid at the end of this section. If you want to change your choice, put a cross through the wrong letter and circle your new choice.
- 1.1The SINE rule is the one to use when you know …(1)A)all three sidesB)two angles and a sideC)all three anglesD)two sides and the angle BETWEEN them
- 1.2The COSINE rule a² = b² + c² − 2bc cos A is used when …(1)A)only one side is knownB)the triangle is right-angledC)two sides and the INCLUDED angle are knownD)two angles and a side are known
- 1.3In △ABC, A = 40°, B = 60° and a = 10. Then b = …(1)A)8,66B)15,32C)13,47D)7,42
- 1.4In △PQR, p = 5, q = 7 and R = 60°. Then r = …(1)A)6,24B)39C)10,44D)2
- 1.5The AREA rule states that the area of a triangle is …(1)A)1/2ab sin CB)1/2 × base × height onlyC)ab sin CD)1/2ab cos C
- 1.6Find the area of △ABC if b = 8, c = 6 and A = 30°.(1)A)24B)12C)48D)20,78
- 1.7In △ABC, a = 9, b = 7 and c = 5. Then cos A = …(1)A)−7B)0,1C)−0,1D)0,83
- 1.8Hence, in that triangle, Â = …(1)A)1,67°B)84,26°C)5,74°D)95,74°
- 1.9The AMBIGUOUS case of the sine rule can arise when …(1)A)two sides and a NON-included angle are givenB)one of the angles is a right angleC)all three sides are givenD)two angles and a side are given
- 1.10In △ABC, if C = 90° the cosine rule becomes …(1)A)c = a + bB)c² = a² + b² − 2abC)c² = a² − b²D)c² = a² + b²
Answer grid — circle your answers for Question 1
| 1.1 | A | B | C | D |
| 1.2 | A | B | C | D |
| 1.3 | A | B | C | D |
| 1.4 | A | B | C | D |
| 1.5 | A | B | C | D |
| 1.6 | A | B | C | D |
| 1.7 | A | B | C | D |
| 1.8 | A | B | C | D |
| 1.9 | A | B | C | D |
| 1.10 | A | B | C | D |
Question 2
[12 MARKS]In the diagram below, △ABC is drawn with BÂC = α, AB̂C = β and AB = c.
- 2.1Write down the size of AĈB in terms of α and β.(1)
- 2.2Show that BC = (c · sin α)/(sin(α + β)).(4)
- 2.3Given that α = 52°, β = 61° and c = 48 m, calculate the length of BC, correct to TWO decimal places.(3)
- 2.4Hence calculate the area of △ABC, correct to TWO decimal places.(4)
Question 3
[15 MARKS]In the diagram below, ABCD is a quadrilateral with the diagonal AC drawn. AB̂C = 106°, BÂC = 31°, AĈD = 46°, AC = 4,6 cm and CD = 10 cm. BC = x. The diagram is not drawn to scale.
- 3.1Calculate the length of x, correct to TWO decimal places.(3)
- 3.2Calculate the area of △ABC, correct to TWO decimal places.(4)
- 3.3Calculate the length of AD, correct to TWO decimal places.(4)
- 3.4Hence calculate the area of quadrilateral ABCD, correct to TWO decimal places.(4)
Question 4
[13 MARKS]The diagram below shows a triangular plot of land PQR with PQ = 45 m, PR = 60 m and QP̂R = 72°. A straight fence QS is built from Q to the point S on PR, with PS = 25 m.
- 4.1Calculate the length of QR, correct to TWO decimal places.(3)
- 4.2Calculate the size of PR̂Q, correct to ONE decimal place.(3)
- 4.3Calculate the area of △PQR, correct to TWO decimal places.(3)
- 4.4Calculate the length of the fence QS, correct to TWO decimal places.(4)
TOTAL: 50 marks
This question paper consists of 4 questions.