y = a sin(kx + p), y = a cos(kx + p) and y = a tan(kx + p) — amplitude, period, horizontal shift, asymptotes, and reading the graphs to answer questions.
1The three parent graphs
y = cos x · amplitude 1, period 360°
y = tan x · no amplitude, period 180°
2The effect of a — amplitude
Amplitude = |a|. It stretches the graph vertically. A negative a flips it in the x-axis.
3The effect of k — period
k does not change the amplitude and a does not change the period. Keep the two effects separate.
4The effect of p — horizontal shift
y = cos(x + 60°) moves left by 60°; y = cos(x − 60°) moves right. The sign inside the bracket is the opposite of the direction you might expect.
5The tangent graph
tan has asymptotes every 180°, starting at 90°, and no maximum or minimum — so it has no amplitude and its range is y ∈ ℝ.
6Reading a trig graph
- 1Amplitude = |2| = 2.The graph reaches 2 and −2.
- 2Period = 360°1 = 360°.k = 1.
- 3Range: −2 ≤ y ≤ 2.Between the two extremes, endpoints included.
- 1Period = 360°2 = 180°.
- 2360° ÷ 180° = 2 complete cycles.Confirmed on the sketch above.
Always write the period and amplitude down before you draw. Then plot the key points every quarter-period — that is where the maxima, minima and x-intercepts sit.
Practice exercises
Work each one out, then click to reveal the answer.
- 1Write down the amplitude of y = 2 sin x.
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2 - 2Write down the period of y = sin 2x.
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360°2 = 180° - 3Write down the range of y = 2 sin x.
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−2 ≤ y ≤ 2 - 4Describe the transformation from y = cos x to y = cos(x + 60°).
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A shift of 60° to the left - 5Write down the period of y = tan 2x.
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180°2 = 90° - 6Write down the equations of the asymptotes of y = tan x for x ∈ [0° ; 360°].
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x = 90° and x = 270° - 7How many complete cycles does y = sin 2x complete in [0° ; 360°]?
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2 - 8Write down the range of y = tan x.
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y ∈ ℝ
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