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Grade 8–9 · Concept lesson

Geometry of 2D Shapes – Part 2

About this video

Part 2 of a Grade 9 worksheet on 2D shapes: the properties of triangles and quadrilaterals — an isosceles triangle, a rectangle, a square with a kite, and a trapezium — used to find unknown angles and sides, with a reason for every step.

What it covers

  • Angles in a triangle add up to 180°, with angles such as 5x + 20°
  • Isosceles triangle: equal angles lie opposite equal sides
  • Rectangle, square and kite properties as reasons
  • Angles in a quadrilateral add up to 360°
  • Trapezium: one pair of parallel sides, so alternate angles

Extra worked examples

✍️ Extra example: in △ABC, Â = 4x + 10°, B̂ = x + 25° and Ĉ = 3x − 15°. Find x and each angle.
  1. 1
    (4x + 10°) + (x + 25°) + (3x − 15°) = 180°
    ∠s of a △ add up to 180°.
  2. 2
    8x + 20° = 180° → 8x = 160° → x = 20°
    Group the like terms, then use the inverses.
  3. 3
    Â = 4(20°) + 10° = 90°, B̂ = 20° + 25° = 45°, Ĉ = 3(20°) − 15° = 45°
    Substitute in brackets. Check: 90° + 45° + 45° = 180° ✓
  4. 4
    B̂ = Ĉ, so AB = AC.
    Equal angles lie opposite equal sides (isos △) — a right-angled isosceles triangle.
✍️ Extra example: ABCD is a kite with AB = AD and CB = CD. Â = 70° and B̂ = 115°. Find D̂ and Ĉ.
  1. 1
    D̂ = B̂ = 115°
    Kite: the angles between the unequal sides are equal.
  2. 2
    Ĉ = 360° − 70° − 115° − 115° = 60°
    ∠s of a quad add up to 360°.

Exercises to try

Work each one out, then click to reveal the answer.

  1. 1
    In △PQR, PQ = PR and Q̂ = 52°. Find R̂ and P̂.
    Show answer ▾
    R̂ = 52° (isos △); P̂ = 180° − 52° − 52° = 76° (∠s of a △)
  2. 2
    PQRS is a rectangle. The diagonal PR splits the corner at P into QP̂R = 2x + 10° and RP̂S = x + 20°. Find x.
    Show answer ▾
    (2x + 10°) + (x + 20°) = 90° (corner of a rectangle) → 3x = 60° → x = 20°, so QP̂R = 50° and RP̂S = 40°
  3. 3
    ABCD is a trapezium with AD ∥ BC. The diagonal BD makes AD̂B = 38°. Find DB̂C, with a reason.
    Show answer ▾
    DB̂C = 38° (alt ∠s; AD ∥ BC)
  4. 4
    △XYZ has X̂ = 2x − 10°, Ŷ = x + 20° and Ẑ = x + 30°. Find x, then classify the triangle.
    Show answer ▾
    4x + 40° = 180° (∠s of a △) → x = 35° → 60°, 55°, 65°: no equal angles, so scalene
  5. 5
    A quadrilateral has angles 3x, 2x + 10°, x + 50° and 2x − 20°. Find x and the largest angle.
    Show answer ▾
    8x + 40° = 360° (∠s of a quad) → x = 40° → 120°, 90°, 90° and 60°; the largest is 120°

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